Can anyone who is expert in turbo c can correct my code here? thanks in advance:?

This is my code:


#include%26lt;stdio.h%26gt;


main()


{


int cas,cnt,ctr,x=1,y=2;


clrscr();


printf("Enter case number[1-4]:");


scanf("%d",%26amp;cas);


switch(cas)


{


case 1:


{ for(cnt=5;cnt%26gt;0;cnt--,x++,y++)


{for(ctr=cnt;ctr%26gt;0;ctr--)


gotoxy(x,y);printf("%d",ctr);


printf("\n");


}


break;


}





case 2:


{ for(cnt=1;cnt%26lt;=5;cnt++)


{for(ctr=cnt;ctr%26lt;=5;ctr++)


printf("%d",cnt);


printf("\n");


}


break;


}


case 3:


{ for(cnt=5;cnt%26gt;0 %26amp;%26amp; ctr%26gt;6;cnt--)


{for(ctr=1;ctr%26lt;=5;ctr++)


printf("%d",ctr);


printf("\n%d\n%d\n%d\n%d",ctr-4,ctr-...


}


break;


}


case 4:


{ for(cnt=1;cnt%26lt;=10;cnt++)


{for(ctr=1;ctr%26lt;=10;ctr++)


printf("%d\t",ctr*cnt);


printf("\n");


}


break;


}


}


getch();


}





--------------------------------


which must produce in case 1:


54321


4321


321


21


1








in case 2:


12345


1234


123


12


1








in case 3:


12345


2


3


4


5








in case 4:


10x10 multiplication table








thx in advance.... :-)

Can anyone who is expert in turbo c can correct my code here? thanks in advance:?
There's no need for a gotoxy in case1. In case 2 you're printing cnt, you should be printing ctr. I've rewritten case 3 to something simpler. Case 4 looks fine to me.





Enjoy.





switch(cas)


{


case 1:


for(cnt=5;cnt%26gt;0;cnt--)


{


for(ctr=cnt;ctr%26gt;0;ctr--)


printf("%d",ctr);


printf("\n");


}


break;





case 2:


{


for(cnt=1;cnt%26lt;=5;cnt++)


{


for(ctr=1;ctr%26lt;=6-cnt;ctr++)


printf("%d",ctr);


printf("\n");


}


}





case 3:


{


for(cnt=1;cnt%26lt;=5;cnt++)


{


printf("%d",cnt);


if (cnt==1)


for(ctr=2;ctr%26lt;=5;ctr++)


printf("%d",ctr);


printf("\n");


}


}


break;





case 4:


{


for(cnt=1;cnt%26lt;=10;cnt++)


{


for(ctr=1;ctr%26lt;=10;ctr++)


printf("%d\t",ctr*cnt);


printf("\n");


}


}


break;


}