Turbo c++...Programming...please help! please...please...i'll give 10 pts!?

here it goes:





Make a program that will input 5 integers and the


output is:





-the total is:


-the largest integer is:


-the smallest integer is:


-the total of the integers if there is negative:





*our instructor told us that we should use array statement and if else statement...





please...please...please...can anyone help me what is the structure of ds program?





i hope u know wat i mean...thank u so much for the help!

Turbo c++...Programming...please help! please...please...i'll give 10 pts!?
Not sure if you want functions or anything fancy so its all going into a main. The program will look something like this... I didnt attempt a compile so dont expect it to be perfect.








#include %26lt;iostream%26gt;


using namespace std;





int const size = 5;


int main()


{


int num[size];





for (int i = 0; i %26lt; size; i++)


{


cout %26lt;%26lt; "Enter integer #" %26lt;%26lt; i %26lt;%26lt; ": ";


cin %26gt;%26gt; num[i];


}





int total;


total = num[0] + num[1] + num[2] + num[3] + num[4];


cout %26lt;%26lt; "Sum of integers is: " %26lt;%26lt; total %26lt;%26lt; endl;





int largest, smallest;


largest = num[0];


smallest = num[0];





for (int h = 0; i %26lt; size; i++)


{


if (num[h] %26lt; smallest)


smallest = num[h];





if (num[h] %26gt; largest)


largest = num[h];


}





cout %26lt;%26lt; "The largest integer is: " %26lt;%26lt; largest %26lt;%26lt; endl;


cout %26lt;%26lt; "The smallest integer is: " %26lt;%26lt; smallest %26lt;%26lt; endl;





return 0;


}
Reply:I believe that Josh's answer will work, but I would check for the smallest and largest as the integers are coming in. I'd also work on the total and have two ideas because i am not sure if you only want the total if one of the integers is negative or not so here is my revision:





#include %26lt;iostream%26gt;


using namespace std;








#define TRUE=1;


#define FALSE=0;





int const size = 5;


int main()


{


int num[size]; //the array for incoming numbers but is really not needed, you can write this without an array


int i; // for counting the incoming numbers


int total; //to find the sum of the incoming numbers


int largest; // the largest integer


int smallest; //the smallest integer


bool negative; // this will be set to true if there is a negative number input - I use 0 for false and 1 for true





i=0; //this will get the first number


cout %26lt;%26lt; "Enter integer #" %26lt;%26lt; i %26lt;%26lt; ": ";


cin %26gt;%26gt; num[i];





largest=num[0];


smallest=num[0];


total=num[0];


if (num[0]%26lt;0) negative=TRUE else negative=FALSE;





for (i = 1; i %26lt; size; i++)


{


cout %26lt;%26lt; "Enter integer #" %26lt;%26lt; i %26lt;%26lt; ": ";


cin %26gt;%26gt; num[i];


if (num[i] %26lt; smallest) smallest = num[i];


if (num[i] %26gt; largest) largest = num[i];


total=total+num[i];


}





cout %26lt;%26lt; "The largest integer is: " %26lt;%26lt; largest %26lt;%26lt; endl;


cout %26lt;%26lt; "The smallest integer is: " %26lt;%26lt; smallest %26lt;%26lt; endl;





// if you want to print out the total no matter what, leave out the if statement and no need for the boolean variable


if (negative=TRUE) cout %26lt;%26lt; "The total of the integers is: " %26lt;%26lt; total %26lt;%26lt; endl;





return 0;


}
Reply:I really don't know.